$A$ galvanometer having a resistance of $20\,\Omega$ and $30\,divisions$ on both sides has a figure of merit of $0.005\,A/division$. The resistance that should be connected in series so that it can be used as a voltmeter up to $15\,V$ is ........... $\Omega$.

$A$ galvanometer has a current range of $10 \text{ mA}$ and a voltage range of $0.75 \text{ V}$. To convert this galvanometer into an ammeter of range $10 \text{ A}$, what is the shunt resistance?

The resistance of an ammeter is $13\, \Omega$ and its scale is graduated for a current up to $100\, A$. After an additional shunt has been connected to this ammeter,it becomes possible to measure currents up to $750\, A$ by this meter. The value of the shunt resistance is:

$A$ moving coil galvanometer allows a full-scale current of $10^{-4} \ A$. $A$ series resistance of $2 \ M\Omega$ is required to convert the above galvanometer into a voltmeter of range $0-5 \ V$. Therefore,the value of shunt resistance required to convert the above galvanometer into an ammeter of range $0-10 \ mA$ is .... $\Omega$.

Consider two identical galvanometers and two identical resistors with resistance $R$. If the internal resistance of the galvanometers is $R_G < R/2$,which of the following configurations yield the maximum voltage range and maximum current range?

$A$ galvanometer of resistance $40\,\Omega$ gives a deflection of $5\, \text{divisions}$ per $mA$. There are $50\, \text{divisions}$ on the scale. The maximum current that can pass through it when a shunt resistance of $2\,\Omega$ is connected is ................ $mA$.